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1Z0-148 Exam Dumps - 1Z0-148 Latest Exam Questions Explanations & Oracle Database: Advanced PL/SQL - Royalholidayclubbed
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1z0-148 PDF DEMO:
QUESTION NO: 1
Examine this function call:
cur_num := DBMS_SQL.TO_CURSOR_NUMBER (cur_val);
Which two statements are true?
A. CUR_VAL can be either a strongly or weakly typed cursor variable.
B. The PL/SQL block can continue to use the cursor variable after this line is executed.
C. CUR_VAL must be a weakly typed cursor variable.
D. CUR_VAL must be opened after this line is executed in the PL/SQL block.
E. CUR_VAL must be opened before this line is executed in the PL/SQL block.
Answer: A,E
QUESTION NO: 2
Which two statements are true with respect to fine-grained access control?
A. It can be used to implement column masking.
B. Separate policies are required for queries versus INSERT/UPDATE/DELETE statements.
C. The DBMS_FGA package is used to set up fine-grained access control.
D. It implements security rules through functions and associates these security rules with tables, views or synonyms.
E. It is implemented by end users.
Answer: B,D
QUESTION NO: 3
Which tablespace is used to store the data collected by PL/Scope?
A. USERS
B. TEMP
C. SYSTEM
D. SYSAUX
E. UNDOTBS1
Answer: D
QUESTION NO: 4
The STUDENTS table exists in your schema.
Examine the DECLARE section of a PL/SQL block:
Which two blocks are valid?
A. BEGINOPEN stcur;cursor3 :=stcur;END;
B. BEGINOPEN cursor1 FOR SELECT * FROM students;cursor2 :=cursor1;END;
C. BEGINOPEN stcur;cursor1 :=stcur;END;
D. BEGINOPEN cursor3 FOR SELECT * FROM students;cursor1 :=cursor3;END;
E. BEGINOPEN cursor1 FOR SELECT * FROM students;stcur :=cursor1;END;
Answer: B,D
QUESTION NO: 5
Which two blocks of code execute successfully?
A. DECLARE
SUBTYPE new_one IS BINARY_INTERGER RANGE 0..9; my_val new_one; BEGIN my_val :=0; END;
B. DECLARE
SUBTYPE new_string IS VARCHAR2 (5) NOT NULL; my_str_new_string; BEGIN my_str := 'abc'; END;
C. DECLARE
SUBTYPE new_one IS NUMBER (2, 1); my_val new_one; BEGIN my_val :=12.5; END;
D. DECLARE
SUBTYPE new_one IS INTEGER RANGE 1..10 NOT NULL; my_val new_one; BEGIN my_val :=2; END;
E. DECLARE
SUBTYPE new_one IS NUMBER (1, 0); my_val new_one; BEGIN my_val := -1;
END;
Answer: A,E
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Updated: May 28, 2022
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