1Z1-071専門試験、Oracle 1Z1-071練習問題 & Oracle Database SQL - Royalholidayclubbed

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そうすれば、あなたは簡単に1z1-071専門試験復習教材のデモを無料でダウンロードできます。そして、あなたは1z1-071専門試験復習教材の三種類のデモをダウンロードできます。あなたは無料で1z1-071専門試験復習教材をダウンロードしたいですか？もちろん、回答ははいです。どんな版でも、Oracle　1z1-071専門試験試験に合格するのには成功への助力です。我々Royalholidayclubbedは最も速いパースする方法をあげるし、PDF版、ソフト版、オンライン版の三つ種類版を提供します。弊社の資料を使って、１００％に合格を保証いたします。

Oracle PL/SQL Developer Certified Associate 1z1-071 夢を持ったら実現するために頑張ってください。

Oracle PL/SQL Developer Certified Associate 1z1-071専門試験 - Oracle Database SQL いまの市場にとてもよい問題集が探すことは難しいです。さて、はやく試験を申し込みましょう。Royalholidayclubbedはあなたを助けることができますから、心配する必要がないですよ。

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Oracle 1z1-071専門試験 - 自分がやっていることに満足していますか。

暇な時間だけでOracleの1z1-071専門試験試験に合格したいのですか。我々の提供するPDF版のOracleの1z1-071専門試験試験の資料はあなたにいつでもどこでも読めさせます。我々もオンライン版とソフト版を提供します。すべては豊富な内容があって各自のメリットを持っています。あなたは各バーションのOracleの1z1-071専門試験試験の資料をダウンロードしてみることができ、あなたに一番ふさわしいバーションを見つけることができます。

実際にはそれは全く不要です。IT認定試験はあなたの思い通りに神秘的なものではありません。

1z1-071 PDF DEMO:

QUESTION NO: 1
Examine the structure of the EMPLOYEES table:
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the name, joining date, and manager for all employees. Newly hired employees are yet to be assigned a department or a manager. For them, 'No Manager' should be displayed in the MANAGER column.
Which SQL query gets the required output?
A. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
RIGHT OUTER JOIN employees mON (e.manager_id = m.employee_id);
B. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
JOIN employees mON (e.manager_id = m.employee_id);
C. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
NATURAL JOIN employees mON (e.manager_id = m.employee_id).
D. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
LEFT OUTER JOIN employees mON (e.manager_id = m.employee_id);
Answer: D

QUESTION NO: 2
View the Exhibit and examine the structure of the CUSTOMERS table.
Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It returns an error because WHERE and HAVING clauses cannot be used in the same SELECT statement.
B. It returns an error because the BETWEEN operator cannot be used in the HAVING clause.
C. It returns an error because WHERE and HAVING clauses cannot be used to apply conditions on the same column.
D. It executes successfully.
Answer: D

QUESTION NO: 3
View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS and TIMES tables.
The PROD_ID column is the foreign key in the SALES table referencing the PRODUCTS table.
The CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the
CUSTOMERS and TIMES tables, respectively.
Examine this command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true?
A. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.
B. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
C. The NEW_SALES table would get created and all the NOT NULL constraints defined on the selected columns from the SALES table would be created on the corresponding columns in the NEW_SALES table.
D. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the selected columns from the SALES table would be created on the corresponding columns in the
NEW_SALES table.
Answer: C

QUESTION NO: 4
A non-correlated subquery can be defined as __________. (Choose the best answer.)
A. A set of sequential queries, all of which must always return a single value.
B. A set of sequential queries, all of which must return values from the same table.
C. A set of one or more sequential queries in which generally the result of the inner query is used as the search value in the outer query.
D. A SELECT statement that can be embedded in a clause of another SELECT statement only.
Answer: C

QUESTION NO: 5
The user SCOTT who is the owner of ORDERS and ORDER_ITEMS tables issues this GRANT command:
GRANT ALL
ON orders, order_items
TO PUBLIC;
What must be done to fix the statement?
A. Separate GRANT statements are required for the ORDERS and ORDER_ITEMS tables.
B. PUBLIC should be replaced with specific usernames.
C. ALL should be replaced with a list of specific privileges.
D. WITH GRANT OPTION should be added to the statement.
Answer: A
Explanation:
http://docs.oracle.com/javadb/10.8.3.0/ref/rrefsqljgrant.html

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Updated: May 28, 2022

by RHC.

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