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1Z0-071模擬体験、1Z0-071実際試験 - Oracle 1Z0-071資格取得講座 - Royalholidayclubbed
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Royalholidayclubbedの試験トレーニング資料はOracleの1z0-071模擬体験認定試験の１００パーセントの合格率を保証します。近年、IT領域で競争がますます激しくなります。IT認証は同業種の欠くことができないものになりました。 君がうちの学習教材を購入した後、私たちは一年間で無料更新サービスを提供することができます。RoyalholidayclubbedのOracleの1z0-071模擬体験試験トレーニング資料は試験問題と解答を含まれて、豊富な経験を持っているIT業種の専門家が長年の研究を通じて作成したものです。 Royalholidayclubbedで、あなたの試験のためのテクニックと勉強資料を見つけることができます。
Oracle PL/SQL Developer Certified Associate 1z0-071 我々Royalholidayclubbedにあなたを助けさせてください。
Oracle PL/SQL Developer Certified Associate 1z0-071模擬体験 - Oracle Database SQL 気楽に試験に合格したければ、はやく試しに来てください。 心配しないでください。私たちを見つけるのはあなたのOracleの1z0-071 資格取得試験に合格する保障からです。
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Oracle 1z0-071模擬体験 - 弊社の商品が好きなのは弊社のたのしいです。
あなたは弊社の商品を買ったら一年間に無料でアップサービスが提供された認定試験に合格するまで利用しても喜んでいます。もしテストの内容が変われば、すぐにお客様に伝えます。弊社はあなた１００％合格率を保証いたします。
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1z0-071 PDF DEMO:
QUESTION NO: 1
Examine the structure of the EMPLOYEES table:
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the name, joining date, and manager for all employees. Newly hired employees are yet to be assigned a department or a manager. For them, 'No Manager' should be displayed in the MANAGER column.
Which SQL query gets the required output?
A. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
RIGHT OUTER JOIN employees mON (e.manager_id = m.employee_id);
B. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
JOIN employees mON (e.manager_id = m.employee_id);
C. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
NATURAL JOIN employees mON (e.manager_id = m.employee_id).
D. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
LEFT OUTER JOIN employees mON (e.manager_id = m.employee_id);
Answer: D
QUESTION NO: 2
A non-correlated subquery can be defined as __________. (Choose the best answer.)
A. A set of sequential queries, all of which must always return a single value.
B. A set of sequential queries, all of which must return values from the same table.
C. A set of one or more sequential queries in which generally the result of the inner query is used as the search value in the outer query.
D. A SELECT statement that can be embedded in a clause of another SELECT statement only.
Answer: C
QUESTION NO: 3
View the Exhibit and examine the structure of the CUSTOMERS table.
Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It returns an error because WHERE and HAVING clauses cannot be used in the same SELECT statement.
B. It returns an error because the BETWEEN operator cannot be used in the HAVING clause.
C. It returns an error because WHERE and HAVING clauses cannot be used to apply conditions on the same column.
D. It executes successfully.
Answer: D
QUESTION NO: 4
View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS and TIMES tables.
The PROD_ID column is the foreign key in the SALES table referencing the PRODUCTS table.
The CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the
CUSTOMERS and TIMES tables, respectively.
Examine this command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true?
A. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.
B. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
C. The NEW_SALES table would get created and all the NOT NULL constraints defined on the selected columns from the SALES table would be created on the corresponding columns in the NEW_SALES table.
D. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the selected columns from the SALES table would be created on the corresponding columns in the
NEW_SALES table.
Answer: C
QUESTION NO: 5
The user SCOTT who is the owner of ORDERS and ORDER_ITEMS tables issues this GRANT command:
GRANT ALL
ON orders, order_items
TO PUBLIC;
What must be done to fix the statement?
A. Separate GRANT statements are required for the ORDERS and ORDER_ITEMS tables.
B. PUBLIC should be replaced with specific usernames.
C. ALL should be replaced with a list of specific privileges.
D. WITH GRANT OPTION should be added to the statement.
Answer: A
Explanation:
http://docs.oracle.com/javadb/10.8.3.0/ref/rrefsqljgrant.html
RoyalholidayclubbedはOracleのSAP C-FIORD-2502認定試験「Oracle Database SQL」に向けてもっともよい問題集を研究しています。 あなたはインターネットでOracleのPalo Alto Networks XSIAM-Analyst認証試験の練習問題と解答の試用版を無料でダウンロードしてください。 IIA IIA-CIA-Part1-CN - Royalholidayclubbedの問題集は最大のお得だね！ Cisco 200-201 - Royalholidayclubbedはまた一年間に無料なサービスを更新いたします。 ABPMP CBPA - Royalholidayclubbedというサイトをクッリクしたらあなたの願いを果たせます。
Updated: May 28, 2022
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