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350-401考題寶典 - 350-401測試引擎 & Implementing Cisco Enterprise Network Core Technologies 350-401 Encor - Royalholidayclubbed
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Royalholidayclubbed為每個需要通過Cisco的350-401考題寶典考試認證的考生提供了一個明確和卓越的解決方案，我們為你提供Cisco的350-401考題寶典考試詳細的問題及答案， 我們團隊的IT專家是最有經驗和資格的，我們的考試測試題及答案幾乎和真實得考試一樣，做到這樣的確很了不起，更重要的是我們Royalholidayclubbed網站在全球範圍內執行這項考試培訓通過率最大。 我們Royalholidayclubbed Cisco的350-401考題寶典考試學習指南可以成為你職業生涯中的燈塔，因為它包含了一切需要通過的350-401考題寶典考試，選擇我們Royalholidayclubbed，可以幫助你通過考試，這是個絕對明智的決定，因為它可以讓你從那些可怕的研究中走出來，Royalholidayclubbed就是你的幫手，你可以得到雙倍的結果，只需要付出一半的努力。 我們Royalholidayclubbed可以為你的IT認證保駕護航，是目前網路上最受歡迎的最可行的培訓資料網站，350-401考題寶典考試是你職業生涯中的一個里程碑，在這種競爭激烈的世界裏，它比以往任何時候都顯得比較重要，我們保證讓你一次輕鬆的通過考試，也讓你以後的工作及日常工作變得有滋有味。
對於 Cisco的350-401考題寶典考試認證每個考生都很迷茫。
我們Royalholidayclubbed的 Cisco的350-401 - Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR)考題寶典的考題資料是按照相同的教學大綱來來研究的，同時也不斷升級我們的培訓材料，所以我們的考試培訓資料包括試題及答案，和實際的考試相似度非常高，所以形成了我們Royalholidayclubbed的通過率也是非常的高，這也是不可否認的事實， 由此知道Royalholidayclubbed Cisco的350-401 - Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR)考題寶典考試培訓資料對考生的幫助，而且我們的價格絕對合理，適合每位IT認證的考生。 但是這並不代表不能獲得高分輕鬆通過考試。那麼，還不知道通過這個考試的捷徑在哪里的你，是不是想知道通過考試的技巧呢？現在我來告訴你，就是利用Royalholidayclubbed的350-401 最新題庫資源考古題。
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350-401 PDF DEMO:
QUESTION NO: 1
Which statement explains why Type 1 hypervisor is considered more efficient than Type 2 hypervisor?
A. Type 1 hypervisor enables other operating systems to run on it
B. Type 1 hypervisor runs directly on the physical hardware of the host machine without relying on the underlying OS
C. Type 1 hypervisor relics on the existing OS of the host machine to access CPU, memory, storage, and network resources.
D. Type 1 hypervisor is the only type of hypervisor that supports hardware acceleration techniques
Answer: B
Explanation:
There are two types of hypervisors: type 1 and type 2 hypervisor.
In type 1 hypervisor (or native hypervisor), the hypervisor is installed directly on the physical server.
Then instances of an operating system (OS) are installed on the hypervisor. Type 1 hypervisor has direct access to the hardware resources. Therefore they are more efficient than hosted architectures.
Some examples of type 1 hypervisor are VMware vSphere/ESXi, Oracle VM Server, KVM and
Microsoft Hyper-V.
In contrast to type 1 hypervisor, a type 2 hypervisor (or hosted hypervisor) runs on top of an operating system and not the physical hardware directly. A big advantage of Type 2 hypervisors is that management console software is not required.
QUESTION NO: 2
What is the correct EBGP path attribute list, ordered from most preferred to the least preferred, that the BGP best-path algorithm uses?
A. weight, local preference, AS path, MED
B. weight, AS path, local preference, MED
C. local preference, weight MED, AS path
D. local preference, weight, AS path, MED
Answer: A
Explanation:
Path Selection Attributes: Weight > Local Preference > Originate > AS Path > Origin > MED > External
> IGP Cost > eBGP Peering > Router ID
QUESTION NO: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.255.255.255.254
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.1.0.0.0.0
D. Permit 10.0.0.0.0.0.0.1
Answer: B
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum:
0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a
"0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all odd- numbered hosts in the 10.0.0.0/24 subnet.
QUESTION NO: 4
Which access controls list allows only TCP traffic with a destination port range of 22-433, excluding port 80?
A. Deny tcp any any ne 80
Permit tcp any any range 22 443
B. Permit tcp any any ne 80
C. Permit tco any any range 22 443
Deny tcp any any eq 80
D. Deny tcp any any eq 80
Permit tco any any gt 21 it 444
Answer: D
QUESTION NO: 5
Which statement about multicast RPs is true?
A. RPs are required for protocol independent multicast sparse mode and dense mode.
B. By default, the RP is needed only to start new sessions with sources and receivers.
C. By default, the RP is needed periodically to maintain sessions with sources and receivers
D. RPs are required only when using protocol independent multicast dense mode.
Answer: B
Explanation:
A rendezvous point (RP) is required only in networks running Protocol Independent Multicast sparse mode (PIM-SM).
By default, the RP is needed only to start new sessions with sources and receivers.
Reference:
https://www.cisco.com/c/en/us/td/docs/ios/solutions_docs/ip_multicast/White_papers/rps.html
For your information, in PIM-SM, only network segments with active receivers that have explicitly requested multicast data will be forwarded the traffic. This method of delivering multicast data is in contrast to the PIM dense mode (PIM-DM) model. In PIM-DM, multicast traffic is initially flooded to all segments of the network. Routers that have no downstream neighbors or directly connected receivers prune back the unwanted traffic.
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Updated: May 28, 2022
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