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1Z0-809考題資訊 - 1Z0-809新版題庫上線 & Java SE 8 Programmer II - Royalholidayclubbed
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如果有我們的軟體有任何更新版本，都會立即推送給客戶。Royalholidayclubbed是可以承諾幫你成功通過你的第一次Oracle 1z0-809考題資訊 認證考試。你買了Royalholidayclubbed的產品，我們會全力幫助你通過認證考試，而且還有免費的一年更新升級服務。 沒有人除外，我們Royalholidayclubbed保證你100%的比例， 今天你選擇Royalholidayclubbed，選擇你要開始的訓練，並通過你的下一次的考題，你將得到最好的資源與市場的相關性和可靠性保證。Royalholidayclubbed Oracle的1z0-809考題資訊考題和答案反映的問題問1z0-809考題資訊考試。 這樣是很不划算。
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1z0-809 PDF DEMO:
QUESTION NO: 1
Given the code fragment:
What is the result?
A. Checking...Checking...
B. A compilation error occurs at line n1.
C. A compilation error occurs at line n2.
D. Checking...
Answer: B
QUESTION NO: 2
Given:
class Book {
int id;
String name;
public Book (int id, String name) {
this.id = id;
this.name = name;
}
public boolean equals (Object obj) { //line n1
boolean output = false;
Book b = (Book) obj;
if (this.id = = b.id) {
output = true;
}
return output;
}
}
and the code fragment:
Book b1 = new Book (101, "Java Programing");
Book b2 = new Book (102, "Java Programing");
System.out.println (b1.equals(b2)); //line n2
Which statement is true?
A. The program prints true.
B. A compilation error occurs. To ensure successful compilation, replace line n2 with:System.out.println (b1.equals((Object) b2));
C. A compilation error occurs. To ensure successful compilation, replace line n1 with:boolean equals
(Book obj) {
D. The program prints false.
Answer: D
QUESTION NO: 3
Given the code fragments:
4. void doStuff() throws ArithmeticException, NumberFormatException, Exception {
5. if (Math.random() >-1 throw new Exception ("Try again");
6. }
and
24. try {
25. doStuff ( ):
26. } catch (ArithmeticException | NumberFormatException | Exception e) {
27. System.out.println (e.getMessage()); }
28. catch (Exception e) {
29. System.out.println (e.getMessage()); }
30. }
Which modification enables the code to print Try again?
A. Replace line 27 with:throw e;
B. Comment the lines 28, 29 and 30.
C. Replace line 26 with:} catch (ArithmeticException | NumberFormatException e) {
D. Replace line 26 with:} catch (Exception | ArithmeticException | NumberFormatException e) {
Answer: C
QUESTION NO: 4
Given the code fragment:
Stream<Path> files = Files.list(Paths.get(System.getProperty("user.home"))); files.forEach (fName ->
{//line n1 try { Path aPath = fName.toAbsolutePath();//line n2 System.out.println(fName + ":"
+ Files.readAttributes(aPath, Basic.File.Attributes.class).creationTime ());
} catch (IOException ex) {
ex.printStackTrace();
});
What is the result?
A. A compilation error occurs at line n1.
B. A compilation error occurs at line n2.
C. The files in the home directory are listed along with their attributes.
D. All files and directories under the home directory are listed along with their attributes.
Answer: C
QUESTION NO: 5
Given that course.txt is accessible and contains:
Course : : Java
and given the code fragment:
public static void main (String[ ] args) {
int i;
char c;
try (FileInputStream fis = new FileInputStream ("course.txt");
InputStreamReader isr = new InputStreamReader(fis);) {
while (isr.ready()) { //line n1
isr.skip(2);
i = isr.read ();
c = (char) i;
System.out.print(c);
}
} catch (Exception e) {
e.printStackTrace();
}
}
What is the result?
A. ueJa
B. The program prints nothing.
C. ur :: va
D. A compilation error occurs at line n1.
Answer: A
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Updated: May 28, 2022
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