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100-101熱門考題 -免費下載100-101考題 & Meta Certified Digital Marketing Associate - Royalholidayclubbed
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因为这是100-101熱門考題考试的最优秀的参考资料。
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不用再猶豫了！請選擇Royalholidayclubbed，它將會是你通過100-101熱門考題認證考試的最好保證。快將Royalholidayclubbed加入你的購物車吧！如果你選擇了Royalholidayclubbed的幫助，我們一定不遺餘力地幫助你通過考試。
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Royalholidayclubbed已經獲得了很多認證行業的聲譽，因為我們有很多的Facebook的100-101熱門考題考古題，100-101熱門考題學習指南，100-101熱門考題考古題，100-101熱門考題考題答案，目前在網站上作為最專業的IT認證測試供應商，我們提供完善的售後服務，我們給所有的客戶買的跟蹤服務，在你購買的一年，享受免費的升級試題服務，如果在這期間，認證測試中心Facebook的100-101熱門考題試題顯示修改或者別的，我們會提供免費為客戶保護，顯示Facebook的100-101熱門考題考試認證是由我們Royalholidayclubbed的IT產品專家精心打造，有了Royalholidayclubbed的Facebook的100-101熱門考題考試資料，相信你的明天會更好。
100-101 PDF DEMO:
QUESTION NO: 1
Which IOS command is used to initiate a login into a VTY port on a remote router?
A. router# login
B. router# telnet
C. router# trace
D. router# ping
E. router(config)# line vty 0 5
F. router(config-line)# login
Answer: B
Explanation:
Explanation/Reference:
VTY ports are telnet ports hence command B will initiate login to the telnet port.
QUESTION NO: 2
A switch has 48 ports and 4 VLANs. How many collision and broadcast domains exist on the switch (collision, broadcast)?
A. 4, 48
B. 48, 4
C. 48, 1
D. 1, 48
E. 4, 1
Answer: B
Explanation:
A switch uses a separate collision domain for each port, and each VLAN is a separate broadcast domain.
QUESTION NO: 3
Refer to the exhibit.
The junior network support staff provided the diagram as a recommended configuration for the first phase of a four-phase network expansion project. The entire network expansion will have over 1000 users on 14 network segments and has been allocated this IP address space.
192.168.1.1 through 192.168.5.255
192.168.100.1 through 192.168.100.255
What are three problems with this design? (Choose three.)
A. The AREA 1 IP address space is inadequate for the number of users.
B. The AREA 3 IP address space is inadequate for the number of users.
C. AREA 2 could use a mask of /25 to conserve IP address space.
D. The network address space that is provided requires a single network-wide mask.
E. The router-to-router connection is wasting address space.
F. The broadcast domain in AREA 1 is too large for IP to function.
Answer: A,C,E
Explanation:
The given IP addresses of areas 1 and 3 along with network masks of 24 cannot accommodate 500 users so are inadequate, while the area 2 is having over capacity so its network mask can be reduced to 25 to accommodate the only 60 users it has.
QUESTION NO: 4
Refer to the exhibit.
Which command would you use to configure a static route on Router1 to network 192.168.202.0/24 with a nondefault administrative distance?
A. router1(config)#ip route 1 192.168.201.1 255.255.255.0 192.168.201.2
B. router1(config)#ip route 192.168.202.0 255.255.255.0 192.168.201.2 1
C. router1(config)#ip route 5 192.168.202.0 255.255.255.0 192.168.201.2
D. router1(config)#ip route 192.168.202.0 255.255.255.0 192.168.201.2 5
Answer: D
Explanation:
Since it has /24 CIDR and it also has a non default administrative distance, the answer has to be option D.
QUESTION NO: 5
Given an IP address of 192.168.1.42 255.255.255.248, what is the subnet address?
A. 192.168.1.8/29
B. 192.168.1.32/27
C. 192.168.1.40/29
D. 192.168.1.16/28
E. 192.168.1.48/29
Answer: C
Explanation:
Explanation/Reference:
248 mask uses 5 bits (1111 1000)
42 IP in binary is (0010 1010)
The base subnet therefore is the lowest binary value that can be written without changing the output of an AND operation of the subnet mask and IP...
1111 1000 AND
0010 1010 equals
0010 1000 - which is .40
/24 is standard class C mask.
Adding the 5 bits from the .248 mask gives /29
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Updated: May 28, 2022
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